Q:

Which equations represent the line that is parallel to 3x - 4y = 7 and passes through the point (-4,-2)? Select twooptions.y=-3x+13x - 4y = -44x - 3y = -3Dy-2=-2(x-4)y+2 = (x + 4)

Accepted Solution

A:
Answer:The equation of another line with given points and parallel to the first line is 3X - 4Y = - 4     Step-by-step explanation:Given as , The equation of one line is 3x - 4y = 7Or, 4y = 3x - 7Or,  y = [tex]\frac{3}{4}[/tex]x - [tex]\frac{7}{4}[/tex]This line is in the form of y = mx + cSo, slop of this line is ( m 1 ) = [tex]\frac{3}{4}[/tex] Now the another line is parallel to this line ,So, for parallel line condition, slop are equal i.e (m 1) = ( m 2)              , Let (m 2) is the slop of another line .So , (m1 ) = (m2) = [tex]\frac{3}{4}[/tex]Again, the another line with slop (m2) passes through points ( - 4 , - 2)So , equation of another line is Y - y1 = (m2) (X - x1)Or, Y + 2 = [tex]\frac{3}{4}[/tex] + (x + 4 )Or, 3X - 4Y = - 4Hence the equation of another line with given points and parallel to the first line is 3X - 4Y = - 4    Answer